A block of iron of mass 7-5kg and of dimensions 12cm - 8cm - 10cm is kept on a table top on its base of side 12cm - 8cm- Calculate a Thrust b Pressure exerted on the table top-Take 1kgf - 10N

Thrust = mg = 7.5 × 10 = 75 N Pressure = FA = 75 10 × 10^ 2× 8 × 10^ 2 = 0.78125 × 10^4 #160; = 7812.5 Pa ...

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Byju's Answer

Standard IX

Physics

Thrust & Pressure

A block of ir...

Question

A block of iron of mass $7.5 k g$ and of dimensions $12 c m \times 8 c m \times 10 c m$ is kept on a table top on its base of side $12 c m \times 8 c m$ . Calculate
a) Thrust
b) Pressure exerted on the table top.
Take $1 k g f = 10 N$

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Solution

Thrust = $m g = 7.5 \times 10 = 75 N$
Pressure = $\frac{F}{A}$
$= \frac{75}{10 \times 10^{- 2} \times 8 \times 10^{- 2}}$
$= 0.78125 \times 10^{4}$
$= 7812.5 P a$

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A block of iron of mass 7.5kg and of dimensions 12cm×8cm×10cm is kept on a table top on its base of side 12cm×8cm. Calculate a) Thrust b) Pressure exerted on the table top.Take 1kgf=10N

Thrust = mg=7.5×10=75NPressure = FA=7510×10−2×8×10−2=0.78125×104 =7812.5Pa

A block of iron of mass $7.5 k g$ and of dimensions $12 c m \times 8 c m \times 10 c m$ is kept on a table top on its base of side $12 c m \times 8 c m$ . Calculate
a) Thrust
b) Pressure exerted on the table top.
Take $1 k g f = 10 N$

Thrust = $m g = 7.5 \times 10 = 75 N$
Pressure = $\frac{F}{A}$
$= \frac{75}{10 \times 10^{- 2} \times 8 \times 10^{- 2}}$
$= 0.78125 \times 10^{4}$
$= 7812.5 P a$