A block of mass 0.1kg is held against a wall by applying a horizontal force of 5N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the friction force acting on the block is
A
2.5N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.98N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4.9N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.49N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B0.98N From FBD R=5N
To find the limiting friction fs=μsR =0.5×5=2.5N ∴ External force (mg)=0.98N<2.5N
The static frictional force (fs)=0.98N