A block of mass 0.8kg is placed on a rough horizontal floor having coefficient of kinetic friction, μ=0.2. Find the acceleration (in m/s2) of the block. Take g=10m/s2
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Solution
Weight of the block, W=mg=0.8×10=8N
FBD of the block,
From FBD, N=20sin53∘+8=24 f=μN=0.2×24=4.8N
And along the horizontal, a=Fm=20cos53∘−fm ⟹a=12−4.80.8=9m/s2