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Question

A block of mass 0.8 kg is placed on a rough horizontal floor having coefficient of kinetic friction, μ=0.2. Find the acceleration (in m/s2) of the block. Take g=10 m/s2

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Solution

Weight of the block, W=mg=0.8×10=8 N
FBD of the block,
From FBD,
N=20sin53+8=24
f=μN=0.2×24=4.8 N
And along the horizontal,
a=Fm=20cos53fm
a=124.80.8=9 m/s2

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