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Question

# A block of mass 1 kg is kept on a rough inclined plane of angle 30o. Find the frictional force acting on the block. Given coefficient of friction μ=0.8

A
4.9 N
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B
6.7 N
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C
10 N
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D
Zero
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Solution

## The correct option is A 4.9 NAs the block is kept on the inclined plane, the normal will be mgcosθ and the force on the block along the plane will be mgsinθ. We also know that Maximum Frictional force fL=μN=μmgcos30∘=0.8×9.8×√32=6.7 N while applied force =mgsin30∘=1×9.8×12=4.9 N<fL (If g is not given, we consider it as 9.8 m/s2) Hence, frictional force will be equal to applied force. f=4.9 N

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