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Question

# A block of mass 10 kg is kept on a fixed rough (μ=0.8) inclined plane of angle of inclination 30. The frictional force acting on the block is

A
50 N
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B
503 N
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C
52 N
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D
54 N
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Solution

## The correct option is A 50 NWhen a block of 10kg is moving n a rough surface and the angle of inclination is 30.the force of static friction is 5kg .wt1kg.wt means a force that is required to accelerate a mass of 1kg with an acceleration of approximately 9.8 m/s2.here the friction force to stop the block is mgsin30\$Since mass is equal to 10 kgforce required =10×sin30 newton=5×gnewton=5kg.wtHence, Option A is correct.

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