You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Range

A block of ma...

Question

A block of mass $1 k g$ is projected from the lowest point up along the inclined plane. If $g = 10 m s^{- 2}$ , the retardation experienced by the block is

\frac{15}{\sqrt{2}} m s^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{5}{\sqrt{2}} m s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{10}{\sqrt{2}} m s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

z e r o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{15}{\sqrt{2}} m s^{- 2}$
$N = m g c o s θ f = μ m g c o s θ a_{r} = \frac{m g s i n θ + μ m g c o s θ}{m} a_{r} = g (s i n θ + μ c o s θ) g (\frac{1}{\sqrt{2}} + \frac{0.5}{\sqrt{2}}) = \frac{10}{\sqrt{2}} + \frac{5}{\sqrt{2}} = \frac{15}{\sqrt{2}}$

Suggest Corrections

Similar questions

Q. A block of mass

1 k g

is projected from the lowest point up along the inclined plane, if

g = 10 m / s^{2}

, the retardation experienced by the block is

Q. A block of mass

1 k g

is projected from the lowest point up along the inclined plane, if

g = 10 m / s^{2}

, the retardation experienced by the block is

Q. A block of mass

2 k g

is lying on a rough inclined plane. The force needed to move the block up the plane with uniform velocity by applying force parallel to the plane is

100 N

. The force needed to move the block up with an acceleration of

2 m s^{- 2}

The system shown in fig. is released from rest with mass 2 kg in contact with the ground. Pulley and spring are massless, and friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves the contact with the ground is (force constant of the spring $k = 40 N m^{- 1} a n d g = 10 m s^{- 2}$ ).

Q. A block of mass 1 kg is kept on incline plane inside lift as shown in figure. If lift starts accelerating up at 2 m/

s^{2}

from rest then work done by frictional force in 1 second is (in J)
( g = 10 m/

s^{2}

)

Friction between block and plane is 0.8.

Join BYJU'S Learning Program

A block of mass 1 kg is projected from the lowest point up along the inclined plane. If g=10 ms−2, the retardation experienced by the block is

The correct option is A 15√2ms−2N=mgcosθf=μmgcosθar=mgsinθ+μmgcosθmar=g(sinθ+μcosθ)g(1√2+0.5√2)=10√2+5√2=15√2

A block of mass $1 k g$ is projected from the lowest point up along the inclined plane. If $g = 10 m s^{- 2}$ , the retardation experienced by the block is

The correct option is A $\frac{15}{\sqrt{2}} m s^{- 2}$
$N = m g c o s θ f = μ m g c o s θ a_{r} = \frac{m g s i n θ + μ m g c o s θ}{m} a_{r} = g (s i n θ + μ c o s θ) g (\frac{1}{\sqrt{2}} + \frac{0.5}{\sqrt{2}}) = \frac{10}{\sqrt{2}} + \frac{5}{\sqrt{2}} = \frac{15}{\sqrt{2}}$