A block of mass 1 kg is released from rest at t = 0 to fall freely under gravity.Find the power of gravitational force acting on it at t= 2sec. $(g = 10 m / s^{2})$ .

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Solution

We have,

$m a s s = 1 k g, t = 2 s,$

Since we know that

$s = u t + \frac{1}{2} a t^{2}$

Here $u = 0$ and $a = g$ where g is acceleration due to gravity

$s = \frac{1}{2} \times 10 \times (2)^{2} = 20 m$

at 2 sec,

$P = f s$ Where P is the power.

Since,
$[f = m g]$

$= 1 \times 10 \times 20$

$= 200$ W

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A block of mass 1 kg is released from rest at t = 0 to fall freely under gravity.Find the power of gravitational force acting on it at t= 2sec. (g=10m/s2).

We have, mass=1kg,t=2s,Since we know that s=ut+12at2Here u=0 and a=g where g is acceleration due to gravitys=12×10×(2)2=20mat 2 sec,P=fs Where P is the power.Since,[f=mg]=1×10×20=200W

A block of mass 1 kg is released from rest at t = 0 to fall freely under gravity.Find the power of gravitational force acting on it at t= 2sec. $(g = 10 m / s^{2})$ .