A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 ms^-2, the frictional force acting on the block is

6 N

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7 N

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4 N

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5 N

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Solution

The correct option is D
5 N

Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N

Applied force = F = ma = 1 × 5 = 5 N

As F < f, so force of friction = 5 N

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A block of mass $1 k g$ lies on horizontal surface in a truck. The coefficient of static friction between the block and the surface is $μ_{s} = 0.6$ . If the acceleration of the truck is $5 m / s^{2}$ , the friction force acting on the block is

Q. Fill in the blanks.
A block of mass

1 k g

lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is

0.6.

If the acceleration of the truck is

5 m / s^{2},

the frictional force acting on the block is ........ Newtons.

Q.
A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is

5 m s^{- 2}

, the frictional force acting on the block is ...............N.

Q. A block of mass

1 k g

lies on a horizontal surface in a truck. The coefficient of friction between the block and the surface is

0.6

. If the acceleration of the truck is

5 m s^{- 2}

, the frictional force acting on the block is

Q. A block of mass

1 kg

lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is

0.6

. If the acceleration of the truck is

5 {m/s}^{2}

, the frictional force acting on the block in Newtons is

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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 ms-2, the frictional force acting on the block is

The correct option is D 5 N Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N Applied force = F = ma = 1 × 5 = 5 N As F < f, so force of friction = 5 N

A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is 5 ms^-2, the frictional force acting on the block is

The correct option is D
5 N

Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N

Applied force = F = ma = 1 × 5 = 5 N

As F < f, so force of friction = 5 N