You visited us 1 times! Enjoying our articles? Unlock Full Access!

Work Done as Dot Product

A block of ma...

Question

A block of mass 10 kg is moving in x-direction with a constant speed of 10 m/s. It is subjected to a retarding force F=-0.1 xJ/m during its travel from x=20m to x=30m. Its final kinetic energy will be

475 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

450 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

275 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 475 J
$K E_{i} = m g h$
$K E_{i} = 0.5 (10) 100 = 500 J$
Work done = $\int_{20}^{30} F x d x$
Work done by F = $\int_{20}^{30} - 0.1 x d x = - 0.1 / 2 (900 - 400) = - 25$
$K E_{f} = 500 - 25 = 475 J$

Suggest Corrections

Similar questions

8 kg

15 m/s

F = 10 x N

x = 10 m

x = 15 m

10 kg

10 m/s

F = - 0.1 x

x = 20

x = 30

10 k g

x

10 m / s

F = - 0.1 x

x = 20

x = 30

10 kg

10 m/s

F = (- 0.1 x) N

x = 20 m

x = 30 m

Join BYJU'S Learning Program