wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass 10 kg is moving in x−direction with a constant speed 10 ms−1. It is subjected to retarding force F=−0.1x J/m during its travel from x=20 m to x=30 m. Find the final kinetic energy.

A
475 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
450 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
275 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
250 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 475 J
As a retarding force is applied, the speed of the body decreases so is the kinetic energy.
This change in KE is the amount of work done by the force.
W=KEiKEf
KEf=KEiW
KEf=KEi3020Fdx
KEf=0.5(10)(102)30200.1xdx
KEf=5000.1[x22]3020=5000.1[30222022]
KEf=50025=475J
Option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work Energy theorem_tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon