Question

A block of mass 10 kg is placed on rough horizontal surface whose coefficient of friction is 0.5. It a horizontal force of 100 N is applied on it, then acceleration of the block will be
[Take g=10 $m{s}^{-2}$]

• A. 10 $m{s}^{-2}$
• B. 5 $m{s}^{-2}$
• C. 15 $m{s}^{-2}$
• D. 0.5 $m{s}^{-2}$

Answer 1

The correct option is B 5 $m{s}^{-2}$

Here, m= 10 kg, g= 10 $m{s}^{-2}$, $\mu$ = 0.5. F=100N
Force of friction,
$f=\mu N=\mu mg=0.5\times 10kg\times 10m{s}^{-2}$=50 N

Force that produces acceleration
F'= F - f = 100N-50N = 50N
$a=\frac{F^{\prime }}{m}=\frac{50N}{10kg}=5m{s}^{-2}$