A block of mass $10 k g$ is resting on floor. The coefficient of friction between the block and ground is 0.2. What is the amount of force needed to just move the block? (Take acceleration due to gravity, $g$ = $10 m / s^{2}$ .)

$70 N$

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$40 N$

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$120 N$

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$20 N$

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Solution

The correct option is D
$20 N$

Given, mass $m$ = $10 k g$

Normal reaction $N$ = $m g$ = $100 N$

Block will just move when the applied force is equal to the frictional force.

Now, Frictional force = Coefficient of friction $\times$ Normal reaction = $0.2 \times 100 = 20 N$

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