A block of mass 10 kg is suspended from two light spring balances, as shown in the figure.
Figure

(a) Both the scales will read 10 kg.
(b) Both the scales will read 5 kg.
(c) The upper scale will read 10 kg and the lower zero.
(d) The readings may be anything but their sums will be 10 kg.

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Solution

(a) Both the scales will read 10 kg.

From the free-body diagram,
K₁x₁ = mg = 10 $\times$ 9.8 = 98 N
K₂x₂ = K₁x₁
So, K₁x₁ = K₂x₂ = 98 N

Therefore, both the spring balances will read the same mass, i.e. 10 kg.

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A block of mass 10 kg is suspended from two light spring balances, as shown in the figure. Figure (a) Both the scales will read 10 kg. (b) Both the scales will read 5 kg. (c) The upper scale will read 10 kg and the lower zero. (d) The readings may be anything but their sums will be 10 kg.

(a) Both the scales will read 10 kg.From the free-body diagram,K1x1 = mg = 10×9.8 = 98 NK2x2 = K1x1 So, K1x1 = K2x2 = 98 NTherefore, both the spring balances will read the same mass, i.e. 10 kg.

A block of mass 10 kg is suspended from two light spring balances, as shown in the figure.
Figure

(a) Both the scales will read 10 kg.
(b) Both the scales will read 5 kg.
(c) The upper scale will read 10 kg and the lower zero.
(d) The readings may be anything but their sums will be 10 kg.

(a) Both the scales will read 10 kg.

From the free-body diagram,
K₁x₁ = mg = 10 $\times$ 9.8 = 98 N
K₂x₂ = K₁x₁
So, K₁x₁ = K₂x₂ = 98 N

Therefore, both the spring balances will read the same mass, i.e. 10 kg.