A block of mass 10 kg, moving in x direction with a constant speed of 10ms−1, is subjected to a retarding force F=0.1xJ/m during its travel from x=−20m to 30m. Its final KE will be
A
275 J
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B
250 J
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C
475 J
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D
450 J
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Solution
The correct option is C 475 J Work done is equal to change in KE. Work done W=∫30−20Fdx=∫30−200.1xdx=0.12[x2]30−20=0.12(900−400)=25 12m(v21−v22)=25 ⇒12×10×(102−v22)=25 KEfinal=12×10×100−25=500−25=475J