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Question

A block of mass 10 kg, moving in x direction with a constant speed of 10ms1, is subjected to a retarding force F=0.1xJ/m during its travel from x=20 m to 30 m. Its final KE will be

A
275 J
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B
250 J
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C
475 J
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D
450 J
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Solution

The correct option is C 475 J
Work done is equal to change in KE.
Work done W=3020Fdx=30200.1xdx=0.12[x2]3020=0.12(900400)=25
12m(v21v22)=25
12×10×(102v22)=25
KEfinal=12×10×10025=50025=475J

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