A block of mass 10 kg slides with velocity of 10 m/s on a rough horizontal surface. It comes to rest after covering a distance of 50 meters. Find the frictional force.

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10N

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100N

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Solution

The correct option is B
10N

u = 10m/s

v = 0

s = 50

$v^{2}$ - $u^{2}$ = 2as

a = -1 m/ $s^{2}$

Friction from is providing this deceleration of the block

fr = ma

fr = 10 $\times$ 1

fr = 10N

so friction is 10N in backward direction.

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A block of mass 10 kg slides with velocity of 10 m/s on a rough horizontal surface. It comes to rest after covering a distance of 50 meters. Find the frictional force.

The correct option is B 10N u = 10m/s v = 0 s = 50 v2- u2 = 2as a = -1 m/ s2 Friction from is providing this deceleration of the block fr = ma fr = 10 × 1 fr = 10N so friction is 10N in backward direction.

The correct option is B
10N

u = 10m/s

v = 0

s = 50

$v^{2}$ - $u^{2}$ = 2as

a = -1 m/ $s^{2}$

Friction from is providing this deceleration of the block

fr = ma

fr = 10 $\times$ 1

fr = 10N

so friction is 10N in backward direction.