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Question

A block of mass 10 kg is placed on rough horizontal surface whose coefficient of friction is 0.5. If a horizontal force of 100 N is applied on it along the surface , then acceleration of block will be [Take g=10 ms2]

A
10 ms2
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B
5 ms2
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C
15 ms2
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D
0.5 ms2
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Solution

The correct option is B 5 ms2
Here, m=10 kg,g=10 ms2,μ=0.5,F=100 N
Force of friction, f=μN=μmg
=0.5×10 kg×10 ms2=50 N
Force that produces acceleration
F=Ff=100 N50 N=50 N
a=Fm=50 N10 kg=5 ms2

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