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Question

A block of mass 1kg is placed on the floor. The coefficient of static friction is 0.2. If a force of 1N is applied to the block, the force of friction is


A

1N

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B

0

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C

varies with the area of contact of the block

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D

2N

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Solution

The correct option is A

1N


The applied force is less than the maximum value of static friction which will be (0.2)(1kg)(10) = 2N. So the force of friction is equal to the applied force.


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