Question

A block of mass 1kg slides down on an inclined plane of inclination 30 degree. Find the work done by the block weight as it slides to 50cm.

Answer 1

Dear student. Since the work done is Fx cos (Q) now here the force is the block's weight = mg = 10 N and the distance travelled = 50 cm = 0.5 m and the angle between the force and the diplacment is 60 deg , as the angle of inclination is 30 and in a right angled trianlge is 180 - 90 - 30 = 60 deg Work done = 10 x 0.5 x cos 60deg = 2.5 Nm Regards.