A block of mass $2.5 k g$ is heated to temperature of $500^{o} C$ and placed on a large ice block. What is the maximum amount of ice that can melt (approx.). Specific heat for the body $= 0.1 C a l / g m^{o} C$

1 k g

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1.5 k g

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2 k g

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2.5 k g

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Solution

The correct option is A $1.5 k g$
(converts units to SI) $0.1 c a l / g m = 0.1 \times 1000 c a l / k g$
Maximum heat released by block,Q= $2.5 \times 0.1 \times 10^{3} \times (500 - 0) = 125000 c a l$
now heat released Q will melt some ice
$Q = m L = m \times 80000$
so, $m = 1.56 k g$

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A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g^–1K^–1; heat of fusion of water = 335 J g^–1).

Q. A copper block of mass 2.5 kg is heated in a furnace to a temperature of

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and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper

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