A block of mass 2kg is hanging with two identical massless springs as shown in figure. The acceleration of the block at the moment the right spring breaks is (g=10m/s2)
A
10m/s2
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B
5m/s2
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C
25m/s2
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D
4m/s2
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Solution
The correct option is A10m/s2 Before cutting, FBD of the block is
2kxcos60∘=mg ⇒kx=mg
After cutting, FBD is
Net vertical force Fy=mg−kxcos60∘=kx−kxcos60∘ (∵mg=kx) Fx=kx−kx2=kx2 Net horizontal force =kxsin60∘=kx×√32 Therefore net force on block after thread is cut =√F2x+F2y=kx