A block of mass 2 kg is initially at rest on a horizontal frictionless surface. A horizontal force →F=(9−x2)^i N acts on it, when the block is at x=0. The maximum kinetic energy of the block between x=0 and x=3 m in Joule is:
A
24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
18
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
15
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C18 Max K.E will at the point where v is max i.ea=dvdt=0