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Question

A block of mass 2 kg is initially at rest on a horizontal frictionless surface. A horizontal force F=(9x2)^i N acts on it, when the block is at x=0. The maximum kinetic energy of the block between x=0 and x=3 m in Joule is:

A
24
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B
20
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C
18
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D
15
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Solution

The correct option is C 18
Max K.E will at the point where v is max i.ea=dvdt=0
F=0
F=0 when x=3
Work done is the change in KE.
W=ΔK.E=30(9x2)dx=[9xx33]30=18J

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