Question

A block of mass 2 kg is moving with a constant velocity on a rough horizontal surface as shown in the figure. The work done by the friction when the block moves by 5m are……
In the above question, the work done by the 10N applied force is…..

Answer 1

Given :

Force F=10 N

Mass of the block M=2 kg

Displacement S=5 m

Solution:

The work done by the frictional force is given by,
$W=F.S\cos 𝛉$
where F is the frictional force
S is the displacement.
𝛉 is the angle between force and displacement.
Therefore,
$$\begin{gathered} W=F.S\cos 0° \\ W=10N🇽5m \\ W=50J \end{gathered}$$

Therefore the work done by the frictional force is $50J$