A block of mass 2kg is placed on a smooth horizontal surface. Two forces F1=20N and F2=5N start acting on the block in opposite directions as shown. If blocks gets displaced by 5m in the direction of net force then work done by F2 is:
A
−75J
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B
75J
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C
−25J
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D
25J
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Solution
The correct option is C−25J The block gets displaced in direction of F1 ∴ Workdone by F2=F2⋅x=5×5cos180o=−25J