A block of mass 2kg is placed on the floor (μ=0.4). A horizontal force of 7N is applied on the block. The force of friction between the block and floor is:
A
8N
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B
7N
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C
5N
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D
6N
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Solution
The correct option is B7N Limitng friction =μN=0.4×2×10=8N
As applied force is less than limiting friction so
Force of friction on block=Applied external force=7N