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Question

A block of mass 2kg is placed on the floor (μ=0.4). A horizontal force of 7N is applied on the block. The force of friction between the block and floor is:
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A
8 N
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B
7 N
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C
5 N
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D
6 N
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Solution

The correct option is B 7 N
Limitng friction =μN=0.4×2×10=8N
As applied force is less than limiting friction so
Force of friction on block=Applied external force=7N

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