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Gravitational Force

A block of ma...

Question

A block of mass 2 kg is thrown vertically with K.E. 490 J. the height at which K.E reduced be:

A

10 m

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B

12.25 m

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C

20 m

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D

25

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Solution

The correct option is B 12.25 m
Energy conservation
$\begin{matrix} K_{1} - K_{2} = m g h = 490 - \frac{490}{2} = 2 \times 9.8 \times h = 490 - 245 = 19.6 h 245 = 19.6 h h = \frac{245}{19.6} h = 12.5 m \end{matrix}$
Hence, Option $B$ is correct.

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