Question

A block of mass 2 kg lies on a plane inclined at an angle of ${30}^0$ with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block?

• A. 10.3 N
• B. 23.8 N
• C. 11.9 N
• D. 6.3 N

Answer 1

The correct option is C 11.9 N

Here, frictional force, $f=\mu R$
$=\mu mgcos\theta =0.7\times 2\times 9.8cos{30}^0$
$=0.7\times 2\times 9.8\times 0.866$=11.9 N