Question

A block of mass $2kg$ rests on a rough inclined plane making an angle of ${30}^{\circ }$ with the horizontal. The coefficient of static friction between the block and the plane is $0.7$. The frictional force on the block is

• A. $7N$
• B. $10\sqrt{3}N$
• C. $10N$
• D. $7\sqrt{3}N$

Answer 1

The correct option is C $10N$

Draw a free body diagram of the given problem.


Given, Mass of block, = 2 kg,
To find, the frictional force on the block, f
It is given that the block is at rest
Therefore, force of friction,$f=mg\sin \theta =2kg\times 10m/s^2\times \sin {30}^{\circ }=10N$