A block of mass $2 k g$ rests on the table. It is pulled horizontally with force $18 N$ . Assume coefficient of kinetic friction between table and the block is $.4$ . Calculate the acceleration of the block.

0.5 m / s^{2}

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1 m / s^{2}

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5 m / s^{2}

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7.5 m / s^{2}

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9 m / s^{2}

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Solution

The correct option is C $5 m / s^{2}$
Frictional force acting on the block opposing the motion $= μ N = μ m g$
$= 0.4 \times 2 \times 10 N = 8 N = f$
Thus net force acting on the block $= F - f$
Hence the acceleration of the block $= \frac{F - f}{m} = \frac{18 - 8}{2} m / s^{2} = 5 m / s^{2}$

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A block of mass 2kg rests on the table. It is pulled horizontally with force 18N. Assume coefficient of kinetic friction between table and the block is .4. Calculate the acceleration of the block.

The correct option is C 5m/s2Frictional force acting on the block opposing the motion=μN=μmg=0.4×2×10N=8N=fThus net force acting on the block=F−fHence the acceleration of the block=F−fm=18−82m/s2=5m/s2

A block of mass $2 k g$ rests on the table. It is pulled horizontally with force $18 N$ . Assume coefficient of kinetic friction between table and the block is $.4$ . Calculate the acceleration of the block.

The correct option is C $5 m / s^{2}$
Frictional force acting on the block opposing the motion $= μ N = μ m g$
$= 0.4 \times 2 \times 10 N = 8 N = f$
Thus net force acting on the block $= F - f$
Hence the acceleration of the block $= \frac{F - f}{m} = \frac{18 - 8}{2} m / s^{2} = 5 m / s^{2}$