A block of mass 2kg rests on a rough inclined plane making an angle of 30∘ with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is
A
9.8N
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B
0.7×9.8×√3N
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C
9.8×√3N
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D
0.7×9.8N
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Solution
The correct option is A9.8N Since the block is at rest, therefore force of friction =mgsinθ=2×9.8×sin30∘=9.8N