Question

A block of mass 20 kg is balanced by three strings A,B& C as shown in figure. Ratio of tensions in string A and B $\left(T_A/T_B\right)$is

• A. $\frac{5}{8}$
• B. $\frac{5\sqrt{3}}{8}$
• C. $\frac{5}{6}$
• D. $\frac{8}{5}$

Answer 1

The correct option is A $\frac{5}{8}$

$T_A\cos {37}^o=T_B\cos {60}^o$

$T_A\times \frac{4}{5}=T_B\times \frac{1}{2}$

Hence $\frac{T_A}{T_B}=\frac{5}{8}$.