wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass 4 kg is kept on ground. The co-efficient of friction between the block and the ground is 0.8. An external force of magnitude 30 N is applied parallel to the ground. The resultant force exerted by the ground on the block is
(Take g=10 m/s2)

A
40 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
60 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
50 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 50 N
FBD of block-

From vertical equilibrium,
N=mg=4×10=40 N
Limiting value of friction,
Ff=μ N=0.8×40=32 N
Since, the value of limiting friction is greater than external force, therefore, the block will not slide and
Ff=Fe=30 N
Now, the resultant force exerted by ground will be,
R=N2+F2f

R=402+302
R=50 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon