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Question

# A block of mass 4 kg is pressed against a wall by two perpendicular horizontal forces as shown in the figure. F1 is perpendicular to the wall and F2 is parallel to the wall. μs=0.8,μk=0.5 and g=10 ms−2 For F1=75 N and F2=30 N, the block remains at rest on the wall. Then, the force of friction (in N) is

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Solution

## As we know that the normal force due to the wall is balanced by external force F1. So, we have F1=75 N N=75 N Now, maximum possible static friction force on the block is given as FS=μsN FS=0.8(75) FS=60 N Now, along vertical downward direction weight of the block acts, which is given as W=mg W=4(10)=40 N Horizontal force on the block applied externally is given as – F=30 N Now, net force parallel to the wall is given as F=√302+402 F=50 N So here, friction force will balance this net force. So, we have Ff=50 N

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