wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass 5 kg is lying on a rough horizontal surface. The coefficients of static and kinetic friction between the block and the surface respectively are 0.7 and 0.5. A horizontal force just sufficient to move the block is applied to it. If the force continues to act even after the block has started moving, what will be the acceleration of the block? Take g=10 ms2.


A

1 ms2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2 ms2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

3 ms2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

4 ms2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

2 ms2


Given m=5 kg,
μs=0.7 and
μk=0.5
Force required to just move the block = Limiting friction, i.e., F=μsmg=0.7×5×10=35 N
Now, once the block starts moving, kinetic friction will act on it. The accelerating force will be given by the difference of applied force and kinetic friction.
Fa=Fμkmg=350.5×5×10=3525=10 N
Acceleration, a=Fam=105=2 ms2
Hence, the correct choice is (b).


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon