Question

A block of mass 5 kg is on a rough horizontal surface and is at rest. Now a force of 24 N is imparted to it with negligible impulse. If the coefficient of kinetic friction is 0.4 and g=9.8 $m/s^2$, then the acceleration of the block is

• A. 0.26 m/s2
• B. 0.39 m/s2
• C. 0.69 m/s2
• D. 0.88 m/s2

Answer 1

The correct option is D

0.88 m/s2

Net force = Applied force - Friction force
$ma=24-\mu mg=24-0.4\times 5\times 9.8=24-19.6$
$\Rightarrow a=\frac{4.4}{5}=0.88m/s^2$