A block of mass $5 kg$ is suspended by an ideal string from an elevator as shown in figure. The elevator is accelerating upward with uniform acceleration $4 {m/s}^{2}$ . If elevators starts form rest, then work done by tension on block in first five second will be

Zero

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1500 J

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2675 J

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3500 J

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Solution

The correct option is D $3500 J$
Answer (2)

$T = m g + m a = 5 (10 + 4)$
$= 70 N$
$S = \frac{1}{2} a t^{2} = \frac{1}{2} \times 4 \times 5^{2} = 50 m$
Now, Work done $W = \to T \cdot \to s = 70 \times 50$
$= 3500 N$

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A block of mass 5 kg is suspended by an ideal string from an elevator as shown in figure. The elevator is accelerating upward with uniform acceleration 4 m/s2. If elevators starts form rest, then work done by tension on block in first five second will be

The correct option is D 3500 JAnswer (2) T=mg+ma=5(10+4) =70 N S=12at2=12×4×52=50 m Now, Work done W=→T⋅→s=70×50 =3500 N

A block of mass $5 kg$ is suspended by an ideal string from an elevator as shown in figure. The elevator is accelerating upward with uniform acceleration $4 {m/s}^{2}$ . If elevators starts form rest, then work done by tension on block in first five second will be

The correct option is D $3500 J$
Answer (2)

$T = m g + m a = 5 (10 + 4)$
$= 70 N$
$S = \frac{1}{2} a t^{2} = \frac{1}{2} \times 4 \times 5^{2} = 50 m$
Now, Work done $W = \to T \cdot \to s = 70 \times 50$
$= 3500 N$