Question

A block of mass 50 kg can slide on a rough horizontal surface. The coefficient of friction between the block and the surface is 0.6. The least force of pull acting at an angle of ${30}^o$ to the upward drawn vertical which causes the block to just slide is:

• A. 29.43 N
• B. 219.6 N
• C. 21.96 N
• D. 294.3 N

Answer 1

The correct option is D 294.3 N

FROM ABOVE FIGURE

$N=50g-Fcos30\circ$

$FSin30\circ =f=\mu N$

$\frac{F}{2}=(500-\frac{F\surd 3}{2})\mu$

$F=(1000-F\surd 3)0.6$

$2.03F=600$

$F=294.3N$