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Standard XII

Physics

Problem Solving

A block of ma...

Question

A block of mass $50 k g$ slides over a horizontal distance of $1 m$ . If the coefficient of friction between their surfaces is $0.2$ ,then work done against friction is:

98 J

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72 J

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56 J

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34 J

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Solution

The correct option is A $98 J$
Work done against friction $(W) = F r i c t i o n \times D i s t a n c e$

$\Rightarrow W = μ m g \times d = 0.2 (50) (9.8) \times 1 = 98 J$
Therefore, A is correct option.

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A block of mass 50kg slides over a horizontal distance of 1m. If the coefficient of friction between their surfaces is 0.2,then work done against friction is:

The correct option is A 98JWork done against friction (W)=Friction×Distance⇒W=μmg×d=0.2(50)(9.8)×1=98JTherefore, A is correct option.

A block of mass $50 k g$ slides over a horizontal distance of $1 m$ . If the coefficient of friction between their surfaces is $0.2$ ,then work done against friction is:

The correct option is A $98 J$
Work done against friction $(W) = F r i c t i o n \times D i s t a n c e$

$\Rightarrow W = μ m g \times d = 0.2 (50) (9.8) \times 1 = 98 J$
Therefore, A is correct option.