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Question

A block of mass 50kg slides over a horizontal distance of 1m. If the coefficient of friction between their surfaces is 0.2,then work done against friction is:

A
98J
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B
72J
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C
56J
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D
34J
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Solution

The correct option is A 98J
Work done against friction (W)=Friction×Distance

W=μmg×d=0.2(50)(9.8)×1=98J
Therefore, A is correct option.

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