Question

A block of mass m= 3 kg slides on a rough inclined plane of coefficient of friction 0.2. Find the resultant force offered by the plane on the block.

Answer 1

R.E.F image

$N=mgcos\theta$

$f=\mu N=\mu mgcos\theta$

Resultant force on block by surface is

$F_{Res}=\sqrt{N^2+f^2}$

$=mgcos\theta \left(\sqrt{1+{\mu }^2}\right)$

$=3\times 10\times \frac{1}{\sqrt{2}}\sqrt{1+0.04}$

$=30\sqrt{2}\times \sqrt{1.04}$

$=30\sqrt{2.08}N$