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Question

A block of mass m is placed on a smooth inclined plane of inclination θ and of mass M, which inturn is placed on a smooth horizontal surface AB as shown. A horizontal force F is applied on the side of the inclined plane so that the block m is just prevented from slipping over the plane.The value of F is
3750.png

A
mgsinθ
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B
mgtanθ
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C
(M+m)gtanθ
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D
(Mm)gtanθ
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Solution

The correct option is C (M+m)gtanθ
If block is not slipping, that means acceleration of m & M is same.
So, acceleration =Fexternal(M+m)
acceleration=F(M+m)
Using pseudo force:
mF(m+M)cosθ=mgsinθ
F=g(M+m)tanθ

54788_3750_ans_f5894abec2234883a5d04fd8da710481.png

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