Question

A block of mass $m$ is placed on smooth inclined wedge of inclination $\theta$ as shown in figure $(\theta ={45}^{\circ })$. The wedge is given an acceleration $a$ towards right, if $a=g$, then net force $m$ block in vertical direction is

• A. $mg$ down
• B. $2mg$, upward
• C. $mg$, up
• D. Zero

Answer 1

The correct option is D Zero


If $a=g\tan \theta$, block does not slip cort wedge
In our case
$a=g\tan 45=g$