Question

A block of mass $m$ is placed on a smooth inclined wedge ABC of inclination $\theta$ as shown in the figure. The wedge is given acceleration $a$ towards the right. The relation between $a$ and $\theta$ for the block to remain stationary on the wedge is

• A. $a=\frac{g}{\cos ec\theta }$
• B. $a=\frac{g}{\sin \theta }$
• C. $a=g\cos \theta$
• D. $a=g\tan \theta$

Answer 1

The correct option is D $a=g\tan \theta$

Using pseudo force,


$ma\cos \theta =mg\sin \theta a=g\tan \theta$