You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Free Body Diagram

A block of ma...

Question

A block of mass $m$ is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of $10 N$ is needed to move the block. Normal reaction $N$ acting is

$50 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$125 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$25 N$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$5 N$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$25 N$

Given

Force needed = $10 N$

Force needed is the amount to overcome friction

Frictional force = Coefficient of friction $\times$ Normal reaction

$\Rightarrow 10$ = $0.4 \times N$

$∴ N$ = $25 N$

Suggest Corrections

Similar questions

Q. A block of mass

0.5 k g

rests against a wall exerting a horizontal force of

10 N

on the wall. If the coefficient of friction between the wall and the block is

0.5

then the frictional force acting on the block will be:

Q. A block of weight 100 N lying in a horizontal surface just to move when a horizontal force of 25N acts on it. Determine the coefficient of static friction.

Q. A block of mass

m

is lying on a horizontal surface. The coefficient of friction between block and the surface is

μ

. The minimum possible force needed to move the block on the surface is

A block of mass m is kept over another block of mass M and the system rests on a horizontal surface (figure 8-E1). A constant horizontal force F acting on the lower block produces an acceleration $\frac{F}{2 (m + M)}$ in the system, the two blocks always move together. (a) Find the coefficient of kinetic friction between the bigger block and the horizontal surface. (b) Find the frictional force acting on the force of friction on the smaller block by the bigger block during a displacement d of the system.

Q. In the given figure a block of weight

10 N

is resting on a horizontal surface. The coefficient of static friction between the block and the surface is

μ_{s} = 0.4

. A force of

3.5 N

will keep the block in uniform motion, once it has been set in motion. A horizontal force of

3 N

is applied to the block, then the block will

Join BYJU'S Learning Program

A block of mass m is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of 10N is needed to move the block. Normal reaction N acting is

The correct option is C 25 N Given Force needed = 10N Force needed is the amount to overcome friction Frictional force = Coefficient of friction× Normal reaction ⇒10 = 0.4×N ∴N = 25 N

A block of mass $m$ is resting on a horizontal surface. The coefficient of friction is 0.4. A horizontal force of $10 N$ is needed to move the block. Normal reaction $N$ acting is

The correct option is C
$25 N$

Given

Force needed = $10 N$

Force needed is the amount to overcome friction

Frictional force = Coefficient of friction $\times$ Normal reaction

$\Rightarrow 10$ = $0.4 \times N$

$∴ N$ = $25 N$