A block of weight 100 N lying in a horizontal surface just to move when a horizontal force of 25N acts on it. Determine the coefficient of static friction.

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Solution

As the 25-N force brings the block to the point of sliding, the frictional force = $μ_{s} N$ .
From force diagram, N= 100 N
$μ_{s} N = 25 \Rightarrow μ_{s} = 0.25$

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A block of weight 100 N lying in a horizontal surface just to move when a horizontal force of 25N acts on it. Determine the coefficient of static friction.

As the 25-N force brings the block to the point of sliding, the frictional force = μsN. From force diagram, N= 100 NμsN=25⇒μs=0.25

As the 25-N force brings the block to the point of sliding, the frictional force = $μ_{s} N$ .
From force diagram, N= 100 N
$μ_{s} N = 25 \Rightarrow μ_{s} = 0.25$