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Question

A block of mass m moving at a velocity v collides with another block of mass 2m at rest. The lighter block comes to rest after collision. Find the coefficient of restitution.


A
12
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B
1
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C
13 
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D
14 
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Solution

The correct option is A 12
From conservation of linear momentum we can see that velocity of 2m will become v2 after collision (as mass is doubled).

Now,

e=Relative velocity of seperationRelative velocity of approach

=v/2v=12

Physics

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