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Question

a block of mass M moving on frictionless horizontal surface collides with spring of spring constant K and compresses it by length L. Maximum momentum of block after collision is ?
A. Ml /k
B. ?MkL
C. zero
D. kL/2M

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Solution

Maximum kinetic energy of the spring is given by:KE = 12kx2where k is the spring constantx is the compression in the stringx = LKE = 12kL2KE also given as P22m12kL2= P22mP = LKM

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