Question

A block of mass 'm' moving with speed 'v' collides with another block of mass '2m' which was at rest. The lighter block comes to rest after the collision. The coefficient of restitution is

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{1}{4}$
• D. $\frac{1}{5}$

Answer 1

The correct option is A

$\frac{1}{2}$

$C.O.M:m_1{u}_1+m_2{u}_2=m_1{v}_1+m_2{v}_2\&e=\frac{v_2-v_1}{u_1-u_2}$

Velocity of 2nd mass = $\frac{m\ast v}{2m}$

e = $\frac{1}{2}$