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Question

A block of mass m slides from the top of an inclined plane of angle of inclination θ and length l. The coefficient of friction between the plane and the block is μ. Then it is observed over a distance d along the horizontal surface having the same coefficient of friction μ, before it comes to a stop. Find the value of d.

A
l[5sinθμcosθ]/μ
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B
l[sinθ2μcosθ]/μ
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C
l[2sinθ3μcosθ]/μ
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D
l[sinθμcosθ]/μ
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Solution

The correct option is B l[sinθμcosθ]/μ
Acceleration of block on rough inclined plane =Netforce/mass
=(mgsinθμmgcosθ)/m
=gsinθμgcosθ

Apply third equation of motion
v2=u2+2as
v2=0+2(gsinθμgcosθ)l
v2=2(gsinθμgcosθ)l
Suppose after travelling distance d it come to rest on horizontal plane
retardation due to friction=μg
Apply third eqauion of motion
v2=u2+2as
0=2(gsinθ)μgcosθ)l2μgd
d=l(gsinθμgcosθ)μ

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