A block of mass mkg strikes an obstacle and moves at an angle of 90∘ to its original direction. If its speed does not change, find the impulse acting on the block.
A
mv
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B
√2mv
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C
2mv
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D
0
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Solution
The correct option is B√2mv Block was moving along +vex− axis direction initially and after striking the obstacle, it moves along +vey− axis direction. i.e initial velocity →vi=v^i and final velocity, →vf=v^j
Then, Impulse, →J=mΔ→v →J=m(→vf−→vi)=m(v^j−v^i) ⇒|→J|=m×√v2+v2 ∴|→J|=√2mv |→J| is the magnitude of impulse acting on the block.