wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block of mass m kg strikes an obstacle and moves at an angle of 90 to its original direction. If its speed does not change, find the impulse acting on the block.


A
mv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 mv
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2 mv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2 mv
Block was moving along +ve x axis direction initially and after striking the obstacle, it moves along +ve y axis direction.
i.e initial velocity vi=v ^i
and final velocity, vf=v ^j

Then, Impulse, J=m Δv
J=m(vfvi)=m (v ^jv ^i)
|J|=m ×v2+v2
|J|=2 mv
|J| is the magnitude of impulse acting on the block.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Momentum Returns
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon