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Question

A block of weight 200N is pulled along a rough horizontal surface at constant speed by a force 100N acting at an angle 300 above the horizontal. The coefficient of friction between the block and the surface is:

A
0.43
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B
0.58
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C
0.75
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D
0.85
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Solution

The correct option is D 0.58
According to question,
As shown in below figure
So,The force on the block long the horizontal is
Fx=100cos30f(i)
f=μ×N(ii)
and also,
200=N+100sin30
N=150N
Now,
substituting the above value in (ii)
f=150×μ
substituting the value of f in (i)
Fx=100cos30150×μ
Hence, the block moves with the constant velocity it means that there is no net force acting on it is horizontal direction,
Fx=0
100cos30150×μ=0
86.6025=150×μ
μ=0.57735


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